How do you graph $2 x + 3 y = 12$ $2x + 3y = 12$ by plotting points?

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Answer 1 · 2018-03-27T12:17:15

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$(2 \cdot 0) + 3 y = 12$ $(2 * 0) + 3y = 12$

$0 + 3 y = 12$ $0 + 3y = 12$

$3 y = 12$ $3y = 12$

$\frac{3 y}{3} = \frac{12}{3}$ $(3y)/color(red)(3) = 12/color(red)(3)$

$y = 4$ $y = 4$ or $(0, 4)$ $(0, 4)$

Second Point: For $y = 0$ $y = 0$

$2 x + (3 \cdot 0) = 12$ $2x + (3 * 0) = 12$

$2 x + 0 = 12$ $2x + 0 = 12$

$2 x = 12$ $2x = 12$

$\frac{2 x}{2} = \frac{12}{2}$ $(2x)/color(red)(2) = 12/color(red)(2)$

$x = 6$ $x = 6$ or $(6, 0)$ $(6, 0)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x + 3y - 12)(x^2+(y-4)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

How do you graph 2x + 3y = 122x+3y=122x + 3y = 12 by plotting points?