How do you graph #2x-3y<=6#?

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Answer 1 · 2015-04-22T05:50:13

Solve #2x-3y<=6# for y.

Subtract 2x from both sides.

#-3y<=-2x+6#

Divide both sides by -3. This will reverse the #<=# symbol to #>=#.

#y>=-2/-3x-6/3#=

#y>=2/3x-2#

Determine two points on the line by using the equation making #y=2/3-2#.

If #x=0, y=2/3*0-2=0-2=-2# Point = #(0,-2)#
If #x=3, y=2/cancel3*cancel3-2=2-2=0# Point = #(3,0)#

Plot the two points and draw a straight line through them. Then shade in the area above the line.
graph{y>=2/3x-2 [-10, 10, -5, 5]}