How do you graph $2 x + 4 y = 8$ $2x+4y=8$ by plotting points?

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Answer 1 · 2017-09-07T17:56:10

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$(2 \cdot 0) + 4 y = 8$ $(2 * 0) + 4y = 8$
$0 + 4 y = 8$ $0 + 4y = 8$
$4 y = 8$ $4y = 8$

$4 \frac{y}{4} = \frac{8}{4}$ $4y/color(red)(4) = 8/color(red)(4)$

$y = 2$ $y = 2$ or $(0, 2)$ $(0, 2)$

Second Point: For $y = 0$ $y = 0$

$2 x + (4 \cdot 0) = 8$ $2x + (4 * 0) = 8$
$2 x + 0 = 8$ $2x + 0 = 8$
$2 x = 8$ $2x = 8$

$\frac{2 x}{2} = \frac{8}{2}$ $(2x)/color(red)(2) = 8/color(red)(2)$

$x = 4$ $x = 4$ or $(4, 0)$ $(4, 0)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x+4y - 8)(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

How do you graph 2x+4y=82x+4y=8 by plotting points?