How do you graph 2x+5y=10 using intercepts?
2 Answers
Graph of
y=−25x+2
graph{-2/5x + 2 [-7, 7, -7, 7]}
Explanation:
The equation of a straight line with gradient
y=mx+c
You have been given all the information you need but to get to this format, need to rearrange:
2x+5y=10
subtracting
−2x+2x+5y=10−2x
5y=−2x+10
Dividing through both sides by
5y5=−2x5+105
y=−25x+2
So now it can be seen that the
The
0=−25x+2
To find the value of
0+25x=−25x+2+25x
25x=2
25x×52=2×52
x=102=5
So the
This means that the graph will cross through:
the
x -intercept(0,5) ; andthe
y -intercept(2,0) .
You can mark these on your graph and then draw a line through them both.
Graph of
y=−25x+2
graph{-2/5x + 2 [-7, 7, -7, 7]}
see explanation.
Explanation:
To find the intercepts.
∙ let x = 0, in the equation, for y-intercept
∙ let y = 0, in the equation, for x-intercept
x=0→0+5y=10→y=2← y-intercept
y=0→2x+0=10→x=5← x-intercept Plot the points (0 ,2) , (5 ,0) and draw a straight line through them. This is the graph of 2x + 5y = 10
graph{-2/5x+2 [-10, 10, -5, 5]}
