How do you graph #2x-7y=14# using intercepts?
1 Answer
Apr 15, 2018
Explanation:
#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArr0-7y=14rArry=-2larrcolor(red)"y-intercept"#
#y=0rArr2x-0=14rArrx=7larrcolor(red)"x-intercept"#
#"plot the points "(0,-2)" and "(7,0)#
#"draw a straight line through them for graph"#
graph{(y-2/7x+2)((x-0)^2+(y+2)^2-0.04)((x-7)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}