How do you graph 2x-7y=142x7y=14 using intercepts?

1 Answer
Apr 15, 2018

"see explanation"see explanation

Explanation:

"to find the intercepts, that is where the graph crosses"to find the intercepts, that is where the graph crosses
"the x and y axes"the x and y axes

• " let x = 0, in the equation for y-intercept" let x = 0, in the equation for y-intercept

• " let y = 0, in the equation for x-intercept" let y = 0, in the equation for x-intercept

x=0rArr0-7y=14rArry=-2larrcolor(red)"y-intercept"x=007y=14y=2y-intercept

y=0rArr2x-0=14rArrx=7larrcolor(red)"x-intercept"y=02x0=14x=7x-intercept

"plot the points "(0,-2)" and "(7,0)plot the points (0,2) and (7,0)

"draw a straight line through them for graph"draw a straight line through them for graph
graph{(y-2/7x+2)((x-0)^2+(y+2)^2-0.04)((x-7)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}