How do you graph -2y=-x+8 by plotting points?
1 Answer
Jun 12, 2018
Explanation:
"one way is to find the intercepts, that is where the"
"graph crosses the x and y axes"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercept"
x=0rArr-2y=8rArry=-4larrcolor(red)"y-intercept"
y=0rArr-x+8=0rArrx=8larrcolor(red)"x-intercept"
"plot the points "(0,-4)" and "(8,0)
"draw a straight line through them for graph"
graph{(y-1/2x+4)((x-0)^2+(y+4)^2-0.04)((x-8)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}