How do you graph -3x-2y=-23x2y=2?

1 Answer
Jun 21, 2017

Convert the given equation to slope intercept form, y=mx+b.y=mx+b. Determine points on the line. Plot the points and draw a straight line through them.

Explanation:

Graph:

-3x-2y=-23x2y=2

Solve for yy to get the equation into slope intercept form: y=mx+by=mx+b, where mm is the slope and bb is the y-intercept (the value of yy when x=0x=0).

Add 3x3x to both sides of the equation.

color(red)cancel(color(black)(3x))-color(red)cancel(color(black)(3x))-2y=3x-2

Simplify.

-2y=3x-2

Divide both sides by -2.

(color(red)cancel(color(black)(-2^1y)))/(color(red)cancel(color(black)(-2^1)))=(3x)/(-2)+(color(red)cancel(color(black)(-2^1))/color(red)cancel(color(black)(-2^1)))

A negative number divided by another negative number gives a positive result.

y=-3/2x+1

Now you can determine several points on the line by choosing values for x and solving for y.

Points

x=-2,y=4

x=0,y=1

x=2,y=2

Plot the points and draw a straight line through them.

graph{-3x-2y=-2 [-10, 10, -5, 5]}