How do you graph 3x - 2y = 63x2y=6 by plotting intercepts?

1 Answer

Solve for the intercepts and find your two intercept points of y-intercept = (0,-3)(0,3) and x-intercept = (2,0)(2,0)

Explanation:

When we plot a graph using intercepts, we are being given 2 points: (0,?) and (?,0) - I'm using the very un-math-like ? to take away a little formality here! We substitute in the two points (or as much as we know about each point), then solve for the other part.

Let's do the y-intercept first. We know that where the graph passes through the y axis, x=0x=0 (we don't move right or left from the origin to find the y axis, so x=0x=0). So with x=0x=0, let's solve for y and find our first point:

3x-2y=63x2y=6
3(0)-2y=63(0)2y=6
-2y=62y=6
y=-3y=3

So that's one point (0,-3)(0,3)

Let's do the x intercept. Following the same reasoning as before, we know that y=0y=0 so let's solve for x:

3x-2y=63x2y=6
3x-2(0)=63x2(0)=6
3x=63x=6
x=2x=2

And that's our other point (2,0)(2,0)

Plot those 2 points, connect them with a straight edge, and you'll get your graph.