How do you graph $3 x + 3 y = 3$ $3x+3y=3$ by plotting points?

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Answer 1 · 2017-10-08T13:38:15

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$(3 \cdot 0) + 3 y = 3$ $(3 * 0) + 3y = 3$

$0 + 3 y = 3$ $0 + 3y = 3$

$3 y = 3$ $3y = 3$

$\frac{3 y}{3} = \frac{3}{3}$ $(3y)/color(red)(3) = 3/color(red)(3)$

$y = 1$ $y = 1$ or $(0, 1)$ $(0, 1)$

Second Point: For $y = 0$ $y = 0$

$3 x + (3 \cdot 0) = 3$ $3x + (3 * 0) = 3$

$3 x + 0 = 3$ $3x + 0 = 3$

$3 x = 3$ $3x = 3$

$\frac{3 x}{3} = \frac{3}{3}$ $(3x)/color(red)(3) = 3/color(red)(3)$

$x = 1$ $x = 1$ or $(1, 0)$ $(1, 0)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-1)^2-0.025)((x-1)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 3y - 3)(x^2+(y-1)^2-0.025)((x-1)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

How do you graph 3x+3y=33x+3y=3 by plotting points?