How do you graph $3 x + 4 y = - 10$ $3x+4y=-10$ using intercepts?

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Answer 1 · 2018-01-26T14:26:32

See a solution process below:

First, we will find the $x$ $x$ intercept by solve the equation for $y =$ $y =$ :

$3 x + (4 \cdot 0) = - 10$ $3x + (4 * 0) = -10$

$3 x + 0 = - 10$ $3x + 0 = -10$

$3 x = - 10$ $3x = -10$

$(3 x) / 3 = - \frac{10}{3}$ $(3x)//color(red)(3) = -10/color(red)(3)$

$x = - \frac{10}{3}$ $x = -10/3$ or $(- \frac{10}{3}, 0)$ $(-10/3, 0)$

Next, we will find the $y$ $y$ intercept by solve the equation for $x =$ $x =$ :

$(3 \times 0) + 4 y = - 10$ $(3 xx 0) + 4y = -10$

$0 + 4 y = - 10$ $0 + 4y = -10$

$4 y = - 10$ $4y = -10$

$(4 y) / 4 = - \frac{10}{4}$ $(4y)//color(red)(4) = -10/color(red)(4)$

$y = - \frac{5}{2}$ $y = -5/2$ or $(0, - \frac{5}{2})$ $(0, -5/2)$

We can then plot the two intercepts on the coordinate plane:

graph{(x^2+(y+(5/2))^2-0.025)((x+(10/3))^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 4y + 10)(x^2+(y+(5/2))^2-0.025)((x+(10/3))^2+y^2-0.025)=0 [-10, 10, -5, 5]}

How do you graph 3x+4y=-103x+4y=−103x+4y=-10 using intercepts?