How do you graph $3 x - 4 y = - 8$ $3x - 4y = -8$ ?

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Answer 1 · 2018-01-19T09:50:50

See below:

For graphing, I like using the slope-intercept form, where the general form is

$y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the $y$ $y$ -intercept.

To get there, solve for $y$ $y$ :

$3 x - 4 y = - 8$ $3x-4y=-8$

$- 4 y = - 3 x - 8$ $-4y=-3x-8$

$y = \frac{3}{4} x + 2$ $y=3/4x+2$

We now have a form where we can pick out the $y$ $y$ -intercept (the point $(0, 2)$ $(0,2)$ . We can use the slope to find another point to plot.

$Slope = \frac{rise}{run}$ $"Slope"="rise"/"run"$ and so we can add 3 to the $y$ $y$ value for every 4 we add to the $x$ $x$ value:

$(0 + 4, 2 + 3) = (4, 5)$ $(0+4,2+3)=(4,5)$

We now have to points so we can graph the line:

graph{((x-0)^2+(y-2)^2-.1)((x-4)^2+(y-5)^2-.1)(3x-4y+8)=0[-15,15,-7,7]}

How do you graph 3x - 4y = -83x−4y=−8 3x - 4y = -8?