How do you graph $3 x - 6 y = 12$ $3x-6y=12$ using the intercepts?

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Answer 1 · 2017-02-04T11:33:35

I tried this:

We find the coordinates of the two intercepts by seting:

$x = 0$ $x=0$ in our equation.
We then get: $3 \cdot 0 - 6 y = 12$ $3*0-6y=12$
and: $y = - \frac{12}{6} = - 2$ $y=-12/6=-2$

$y = 0$ $y=0$ in our equation.
We then get: $3 x - 6 \cdot 0 = 12$ $3x-6*0=12$
and: $x = \frac{12}{3} = 4$ $x=12/3=4$

So our intercepts have coordinates:
$(0, - 2)$ $(0,-2)$
$(4, 0)$ $(4,0)$

These two points are enough to plot the straight line described by our equation:
enter image source here

How do you graph 3x−6y=123x-6y=12 using the intercepts?