How do you graph $3x-y=3$ using intercepts?

Question

10287 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-15T23:53:12

Rearrange the equation in terms of $y$ .

Subtract $3x$ from both sides:

$- y = -3x + 3$

Multiply by $-1$

$y = 3x - 3$

The $y$ axis intercept is $-3$ this occurs when $x$ is $0$

Rearranging in terms of $x$

$x = (y + 3)/3$

The $x$ axis intercept occurs when $y = 0$

$x = (0 + 3)/3 = 1$

The coordinates for graphing are:

$( 0 , -3 ) and ( 1 , 0 )$

How do you graph 3x-y=33x-y=3 using intercepts?