How do you graph $3 x + y = 6$ $3x+y=6$ using intercepts?

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Answer 1 · 2016-09-26T10:44:06

find out the intercept and join them together

subtitute $y = 0$ $y=0$ to find x intercepts

when $y = 0$ $y=0$

$3 x = 6$ $3x=6$
$x = 2$ $x=2$

x intercepts is 2

subtitute $x = 0$ $x=0$ to find y intercepts

when $x = 0$ $x=0$

$y = 6$ $y=6$

y intercepts is 3

since this is a linear equation $y = m x + c$ $y=mx+c$ ,we can draw the graph by draw a line to join the two intercept point

graph{3x+y=6 [-11.08, 14.58, -3.73, 9.1]}

How do you graph 3x+y=63x+y=63x+y=6 using intercepts?