How do you graph $4 x + 1 = 9$ $4x+1=9$ by plotting points?

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Answer 1 · 2016-07-19T12:41:52

$x = 2$ $x=2$ is a vertical line through $(2.0)$ $(2.0)$

Let's start off by simplifying the equation a bit.

$4 x = 9 - 1 = 8$ $4x = 9-1 =8$

$4 x = 8 \Rightarrow x = 2$ $4x = 8 " "rArr x = 2$

$x = any number$ $x= "any number"$ is the equation of a vertical line which passes through the x-axis at $x = 2$ $x =2$

You can plot any number of points, but you will find that no matter what y-value is used, the x-value is always 2.

All the points will be $(2, y)$ $(2, y)$

Vertical lines cannot be written in standard form $y = m x + c$ $y = mx +c$ .
They have a slope which is undefined.
They do not have a y=term at all.

How do you graph 4x+1=94x+1=9 by plotting points?