How do you graph 4x−3y=12 using intercepts?
1 Answer
Aug 18, 2017
Explanation:
find the intercepts as follows
∙ let x = 0, in the equation for y-intercept
∙ let y = 0, in the equation for x-intercept
x=0→0−3y=12⇒y=−4← y-intercept
y=0→4x−0=12⇒x=3← x-intercept
plot the points (0,−4),(3,0)
and draw a straight line through them for graph
graph{4/3x-4 [-10, 10, -5, 5]}