How do you graph $-5x+2y=10$ using intercepts?

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Answer 1 · 2016-08-26T22:22:08

The intercepts are $(-2, 0) and (0, 5)$

All points along the $x-$ axis have their y- value =0.

All points along the $y-$ axis have their x- value =0.

To find the $y$ intercept of a line,make x = 0.

To find the $x$ intercept of a line,make y = 0.

Once you have the $x- and y-$ intercepts, you have two points of the line.

Draw a line which passes through the two points.

$-5color(red)(x) +2color(blue)(y) = 10$

For $x-$ int, $color(blue)(y=0)$

$rarr -5x +2color(blue)((0)) = 10$

$-5x = 10" div -5$

$x = 10/(-5) = -2 " "x = -2$

For $y-$ int, $color(red)(x=0)$

$rarr -5color(red)((0))x +2y = 10$

$2y= 10" "div 2$

$y = 10/(2) = 5 " "y = 5$

How do you graph -5x+2y=10-5x+2y=10 using intercepts?