How do you graph $- 7 y + 2 x + 14$ $-7y + 2x + 14$ using intercepts?

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Answer 1 · 2017-07-18T12:28:43

The equation given is a line. $- 7 y + 2 x + 14 = 0$ $-7y+2x+14=0$

We put values for $x$ $x$ and get values out for $y$ $y$ or vise versa

So we find two point from which the line goes through

Let's start with $x = 0$ $x=0$

$- 7 y + 2 x + 14 = 0 \Rightarrow - 7 y + 14 = 0 \Rightarrow y = 2$ $-7y+2x+14=0=>-7y+14=0=>y=2$

so the first point is $A_{1} (0, 2)$ $A_1(0,2)$

Now let's pu $y = 0$ $y=0$

$- 7 y + 2 x + 14 = 0 \Rightarrow 2 x + 14 = 0 \Rightarrow x = - 7$ $-7y+2x+14=0=>2x+14=0=>x=-7$

So the second point is $A_{2} (- 7, 0)$ $A_2(-7,0)$

The graph is a line that goes through $A_{1}$ $A_1$ and $A_{2}$ $A_2$
graph{-7y+2x+14=0 [-10, 10, -5, 5]}

How do you graph −7y+2x+14 -7y + 2x + 14 using intercepts?