How do you graph $f (x) = - 2 x - 5$ $f(x) = -2x - 5$ ?

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Answer 1 · 2018-03-19T22:59:15

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$f (x) = (- 2 \cdot 0) - 5$ $f(x) = (-2 * 0) - 5$

$f (x) = 0 - 5$ $f(x) = 0 - 5$

$f (x) = - 5$ $f(x) = -5$ or $(0, - 5)$ $(0, -5)$

Second Point: For $x = - 2$ $x = -2$

$f (x) = (- 2 \cdot - 2) - 5$ $f(x) = (-2 * -2) - 5$

$f (x) = 4 - 5$ $f(x) = 4 - 5$

$f (x) = - 1$ $f(x) = -1$ or $(- 2, - 1)$ $(-2, -1)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+5)^2-0.1075)((x+2)^2+(y+1)^2-0.1075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + 2x + 5)(x^2+(y+5)^2-0.1075)((x+2)^2+(y+1)^2-0.1075)=0 [-20, 20, -10, 10]}

How do you graph f(x)=−2x−5f(x) = -2x - 5?