How do you graph $R (x) = \frac{x + 2}{x^{2} - 4}$ $R(x) = (x + 2)/(x^2 - 4)$ ?

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How do you graph $R (x) = \frac{x + 2}{x^{2} - 4}$ $R(x) = (x + 2)/(x^2 - 4)$ ?

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Answer 1 · 2015-07-08T08:17:34

The graph would be the graph of $\frac{1}{x}$ $1/x$ translated horizontally to the right by 2 units, with a hole at x= -2

Explanation:

R(x) on simplification is $\frac{1}{x - 2}$ $1/(x-2)$ .

This can be easily graphed by translating the graph of function $\frac{1}{x}$ $1/x$ horizontally to the right by 2 units. It would have an asymptote at x=2. There would be hole at x= -2 in the graph for R(x)

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How do you graph $R (x) = \frac{x + 2}{x^{2} - 4}$ $R(x) = (x + 2)/(x^2 - 4)$ ?

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