How do you graph $tan (\frac{x}{2}) + 1$ $tan(x/2) + 1$ ?

Question

2608 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-29T12:19:56

graph{tan(x/2)+1 [-10, 10, -5, 5]}

You first have to know what the graph of $tan (x)$ $tan(x)$ looks like

graph{tan(x) [-10, 10, -5, 5]}

It has vertical assymptotes at $π$ $pi$ intervals so the period is $π$ $pi$ and when x=0 y=0

So if you have $tan (x) + 1$ $tan(x)+1$ it shifts all the y values up by one

$tan (\frac{x}{2})$ $tan(x/2)$ is a vertical shift and it doubles the period to $2 π$ $2pi$

graph{tan(x/2)+1 [-10, 10, -5, 5]}

How do you graph tan(x2)+1tan(x/2) + 1?