How do you graph the arithmetic sequence a_n=-0.25+0.45n?

1 Answer
Mar 17, 2018

As below.

Explanation:

y = mx + c

Given equation is

a_n = 0.45 n - 0.25

Slope of the line m = 0.45

a_1 = 0.45 - 0.25 = 0.2

a_2 = 0.45 * 2 - 0.25 = 0.9 - 0.25 = 0.65

a_3 = 0.45 * 3 - 0.25 = 1.1

a_3 - a_2 = a_2 - a_1 = d = 0.65 - 0.2 = 0.45

graph{0.45x - 0.25 [-10, 10, -5, 5]}