How do you graph the arithmetic sequence $a_{n} = - 0.25 + 0.45 n$ $a_n=-0.25+0.45n$ ?

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Answer 1 · 2018-03-17T08:11:32

As below.

$y = m x + c$ $y = mx + c$

Given equation is

$a_{n} = 0.45 n - 0.25$ $a_n = 0.45 n - 0.25$

Slope of the line $m = 0.45$ $m = 0.45$

$a_{1} = 0.45 - 0.25 = 0.2$ $a_1 = 0.45 - 0.25 = 0.2$

$a_{2} = 0.45 \cdot 2 - 0.25 = 0.9 - 0.25 = 0.65$ $a_2 = 0.45 * 2 - 0.25 = 0.9 - 0.25 = 0.65$

$a_{3} = 0.45 \cdot 3 - 0.25 = 1.1$ $a_3 = 0.45 * 3 - 0.25 = 1.1$

$a_{3} - a_{2} = a_{2} - a_{1} = d = 0.65 - 0.2 = 0.45$ $a_3 - a_2 = a_2 - a_1 = d = 0.65 - 0.2 = 0.45$

graph{0.45x - 0.25 [-10, 10, -5, 5]}

How do you graph the arithmetic sequence an=−0.25+0.45na_n=-0.25+0.45n?