How do you graph the equation by plotting points $-x + 3y = -9$ ?

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Answer 1 · 2016-01-13T03:46:39

Refer the explanation section

Given -

$-x+3y=-9$

It is in the form >
$ax+by=c$

Then -

Y- intercept is $y=c/b=(-9)/3=-3$

One of the points is $(0, -3)$

X-Intercept is $x=c/a=(-9)/(-1)=9$

Another point is $(9, 0)$

Plot these two points and join them with the help of a straight line.

Refer the picture

How do you graph the equation by plotting points -x + 3y = -9-x + 3y = -9?