How do you graph the line $2x-3y=0$ ?

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Answer 1 · 2016-07-03T02:50:13

Solve for $y$

$2x-3y=0$

$2x=3y$

$y=2/3x$

Consider $y=mx+b$ where m is the slope and b is the y-intercept

graph{2/3x [-4.178, 5.824, -2.35, 2.65]}

The $y$ -intercept is $0$ so there is a point at $0,0$ .

The slope is $2/3$ so start from $0$ and move up $2$ and to the right $3$ and there is another point. Draw a straight line through these points. .

How do you graph the line 2x-3y=02x-3y=0?