Question

How do you graph the line `3x-4y-8=0`?

Answer 1

you will have to graph the line

`y=3/4x-2`

where `3/4` is the gradient of the line and it has a `y`-intercept of `-2`.

Explanation:

you would have to rearrange the given equation into the

`y=mx+c`

form, where `m` is the gradient of the straight line and `c` is the `y`-intercept.

graph{3/4x-2 [-10, 10, -5, 5]}

Answer 2

As below.

Explanation:

`3x - 4y - 8 = 0`

For x = 0, -4y - 8 = 0 " or " y-intercept = -2#

For y = 0, 3x = 8 " or " x-intercept = 8/3#

Now we know, x intercept as 8/3 and y intercepts as -2#

We can mark the intercepts on the graph and join them to draw the line.

graph{(3/4)x - 2 [-10, 10, -5, 5]}

Answer 3

Graph the line by finding the intercepts.

Explanation:

Graph:

`3x-4y-8=0`

Add `8` to both sides of the equation to get the equation into standard form:

`Ax+By=C`, so that

`3x-4y=8`

You can graph this equation by finding the intercepts.

X-intercept: value of `x` when `y=0`

Substitute `0` for `y` and solve for `x`.

`3x-4(0)=8`

`3x=8`

Divide both sides by `3`.

`(3x)/3=8/3`

`x=8/3` or `~~2.667`

The x-intercept is `(8/3,0)` or `~~2.667` Plot this point.

Y-intercept: value of `y` when `x=0`.

Substitute `0` for `x` and solve for `y`.

`3(0)-4y=8`

`-4y=8`

Divide both sides by `-4`.

`(-4y)/(-4)=8/(-4)`

`y=-8/4`

Simplify.

`y=-2`

The y-intercept is `(0,-2)` Plot this point.

Draw a straight line through the points.

graph{3x-4y=8 [-10, 10, -5, 5]}