How do you graph the line given (2, -1) with slope of 3?

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How do you graph the line given (2, -1) with slope of 3?

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Answer 1 · 2016-04-25T05:21:27

You plot the coordinates then use the slope of $3$ $3$ as $\frac{3}{1}$ $3/1$

Explanation:

To plot the point, move $2$ $2$ to the right on the $x$ $x$ -axis then $1$ $1$ down ( $y$ $y$ -axis). Then look at the slope. $3$ $3$ is also equal to $\frac{3}{1}$ $3/1$ (3 over 1) as a fraction.

In a fraction there are two parts, the numerator (top number in this case $3$ $3$ ) and the denominator (bottom number in this case $1$ $1$ ).

The numerator shows the rise (number of spaces you go along the $y$ $y$ -axis) and the denominator shows the run (number of spaces you go along the $x$ $x$ -axis).

So from the point $(2, - 1)$ $(2,-1)$ , you go up (since it is a positive slope) $3$ $3$ spaces and to the right $1$ $1$ space.

graph{3x-7 [-10, 10, -5, 5]} .

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How do you graph the line given (2, -1) with slope of 3?

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