How do you graph the line through point (2,6) and slope m=2/3?
1 Answer
See a solution process below:
Explanation:
First, we can plot the point given in the problem:
graph{((x-2)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}
Slope is
The slope in the problem is
Therefore,
The change in the
The change in the
We can find another point by adding these to the values from the point in the problem:
We can now plot this point:
graph{((x-2)^2+(y-6)^2-0.1)((x-5)^2+(y-8)^2-0.1)=0 [-20, 20, -10, 10]}
Now, we can draw a line through the two points:
graph{(y-2/3x - 4.6)((x-2)^2+(y-6)^2-0.1)((x-5)^2+(y-8)^2-0.1)=0 [-20, 20, -10, 10]}