How do you graph the line #y=-1/2x+5#?

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Answer 1 · 2017-09-28T13:41:35

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (-1/2 * 0) + 5#

#y = 0 + 5#

#y = 5# or #(0, 5)#

Second Point: For #x = 4#

#y = (-1/2 * 4) + 5#

#y = -2 + 5#

#y = 3# or #(4, 3)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-5)^2-0.1)((x-4)^2+(y-3)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x^2+(y-5)^2-0.1)((x-4)^2+(y-3)^2-0.1)(y+0.5x-5)=0 [-20, 20, -10, 10]}