How do you graph the line $y = \frac{1}{3} x + 3$ $y=1/3x+3$ ?

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Answer 1 · 2017-11-06T15:20:12

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (\frac{1}{3} \cdot 0) + 3$ $y = (1/3 * 0) + 3$

$y = 0 + 3$ $y = 0 + 3$

$y = 3$ $y = 3$ or $(0, 3)$ $(0, 3)$

Second Point: For $x = 3$ $x = 3$

$y = (\frac{1}{3} \cdot 3) + 3$ $y = (1/3 * 3) + 3$

$y = 1 + 3$ $y = 1 + 3$

$y = 4$ $y = 4$ or $(1, 4)$ $(1, 4)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.025)((x-3)^2+(y-4)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - (1/3)x - 3)(x^2+(y-3)^2-0.025)((x-3)^2+(y-4)^2-0.025)=0 [-10, 10, -5, 5]}

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