How do you graph the point 1 + 2i on a complex plane?
1 Answer
Jan 11, 2017
See the graph and the explanation.
Explanation:
graph{(x-1)^2+(y-2)^2-0.01=0 [-10, 10, -5, 5]}
Eyebrows might be raised on my statement that a point is a null
vector that can be associated with any arbitrary direction in space
that is chosen to move away, from the point.
Yet, to make it visible, we locate a point by making a dimensional-
dot.
In a computer monitor, a few glowing pixels mark the point. It is
really a point circle that has a befittingly small radius.
In the inserted graph, I have plotted the point
P(1, 2) to represent the complex number (1, 2i) by the circle