How do you graph using the intercepts for $- 10 x + 7 y = - 25$ $-10x+7y=-25$ ?

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Answer 1 · 2018-08-13T17:21:07

To graph the line, simply connect the intercepts $(\frac{5}{2}, 0)$ $(5/2, 0)$ and $(0, - \frac{25}{7})$ $(0, -25/7)$ .

The x-intercept is the point at which the y-coordinate is $0$ $0$ .

The y-intercept is the point at which the x-coordinate is $0$ $0$ .

Substitute $y = 0$ $color(red)(y = 0)$ to find the x-intercept.

$- 10 x + 7 (0) = - 25$ $-10x + 7(color(red)0) = -25$

$- 10 x = - 25$ $-10x = -25$

$x = \frac{5}{2}$ $x = 5/2$

Therefore the x-intercept is $(\frac{5}{2}, 0)$ $(5/2, color(red)0)$ .

Substitue $x = 0$ $color(red)(x = 0)$ to find the y-intercept.

$- 10 (0) + 7 y = - 25$ $-10(color(red)0) + 7y = -25$

$7 y = - 25$ $7y = -25$

$y = - \frac{25}{7}$ $y = -25/7$

Therefore the y-intercept is $(0, - \frac{25}{7})$ $(color(red)0, -25/7)$ .

To graph the line, simply connect the two points.

How do you graph using the intercepts for −10x+7y=−25 -10x+7y=-25?