How do you graph using the intercepts for 3x2y=3?

1 Answer
Aug 3, 2018

see explanation

Explanation:

to find the intercepts, that is where the graph crosses
the x and y axes

let x = 0, in the equation for y-intercept

let y = 0, in the equation for x-intercept

x=02y=3y=32y-intercept

y=03x=3x=1x-intercept

Plot the points (0,32) and (1,0)

Draw a straight line through them for graph
graph{(y-3/2x-3/2)((x-0)^2+(y-3/2)^2-0.04)((x+1)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}