How do you graph using the intercepts for 3x−2y=−3?
1 Answer
Aug 3, 2018
Explanation:
to find the intercepts, that is where the graph crosses
the x and y axes
∙ let x = 0, in the equation for y-intercept
∙ let y = 0, in the equation for x-intercept
x=0⇒−2y=−3⇒y=32←y-intercept
y=0⇒3x=−3⇒x=−1←x-intercept
Plot the points (0,32) and (−1,0)
Draw a straight line through them for graph
graph{(y-3/2x-3/2)((x-0)^2+(y-3/2)^2-0.04)((x+1)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}