How do you graph using the intercepts for $4 x - 3 y = - 19$ $4x-3y=-19$ ?

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Answer 1 · 2016-05-21T10:51:28

$y_{intercept} = + \frac{19}{3}$ $y_("intercept") = +19/3$
$x_{intercept} = - \frac{19}{4}$ $x_("intercept")=-19/4$

Mark you points and draw a straight line through them.

Think about where the graph axis cross. The y-axis is where $x = 0$ $x=0$ and the x-axis is where $y = 0$ $y=0$

To find $y_{intercept}$ $y_("intercept")$ set $x = 0$ $x=0$

$4 x - 3 y = - 19 \to 4 (0) - 3 y = - 19$ $color(brown)(4x-3y=-19)color(blue)(" "->" "4(0)-3y=-19)$

Divide both sides by $(- 3)$ $(-3)$

$y_{intercept} = \frac{- 19}{- 3} = + \frac{19}{3}$ $y_("intercept")=(-19)/(-3) = +19/3$
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To find $x_{intercept}$ $x_("intercept")$ set $y = 0$ $y=0$

$4 x - 3 y = - 19 \to 4 x - 3 (0) = - 19$ $color(brown)(4x-3y=-19)color(blue)(" "->" "4x-3(0)=-19)$

Divide both sides by +4

$x_{intercept} = - \frac{19}{4}$ $x_("intercept")=-19/4$

How do you graph using the intercepts for 4x−3y=−194x-3y=-19?