How do you graph using the intercepts for #4x-3y=-20#?
1 Answer
Dec 20, 2015
Plot the intercept points and draw a straight line through them.
Explanation:
x-intercept
when
point at
y-intercept
when
point at
Plotting the two points and drawing a line through them should give a graph of the form:
graph{(4x-3y+20)((x+5)^2+y^2-0.01)(x^2+(y-(20/3))^2-0.01)=0 [-9.6, 8.18, -1.484, 7.405]}