How do you graph using the intercepts for 5x + 2y = -2?

1 Answer
Alan P.
Nov 9, 2015

Plot the intercept points and draw a straight line through them
graph{(5x+2y+2) ((x+2/5)^2+y^2-0.01)(x^2+(y+1)^2-0.01)=0 [-4.93, 4.934, -2.465, 2.465]}

Explanation:

The x and y intercepts give us two points on the line defined by the linear equation.

The x-intercept is the value of x when y=0 (for all points on the X-axis y=0)

Given 5x+2y=-2
when y=0
rArrcolor(white)("XXX")x=-2/5
which gives the point (-2/5,0)

Similarly for the y-intercept
we get the point (0,-1)

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