How do you graph using the intercepts for #- 5x + 3y = 19#?

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Answer 1 · 2018-05-05T09:49:00

Below

For x-intercept, let #y=0#

ie #-5x+3y=19#
#-5x+3(0)=19#
#-5x=19#
#x=-19/5#

#(-19/5)# is your x-intercept

For y-intercept, let #x=0#

ie #-5x+3y=19#
#-5(0)+3y=19#
#3y=19#
#y=19/3#

#(0,19/3)# is your y-intercept

Using your two intercepts, plot them on the graph and join the points together.

graph{-5x+3y=19 [-10, 10, -5, 5]}