Question

How do you graph using the intercepts for `5x+3y=53`?

Answer 1

`color(purple)("The two points are " (53/5,0), (0, 53/3)`

Explanation:

`5x + 3y = 53`

![https://www.tutorpace.com/algebra/linear-equations-online-tutoring]()

`Intercept form of equation is`x / a + y / b = 1#

Converting the given equation to intercept form,

`(5/53) x + (3/53) y = 1`

`x / (53/5) + y / (53/3) =1`

Hence, `"x-intercept " = 53/5, " y-intercept " = 53/3`

`color(purple)("The two points are " (53/5,0), (0, 53/3)`

Now we can plot the graph knowing two points on a line.

graph{-(5/3) x + (53/3) [-10, 10, -5, 5]}