How do you graph using the intercepts for $7 x + 4 y = 17$ $7x + 4y = 17$ ?

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Answer 1 · 2018-08-08T20:37:02

Put zero in for both x and y solve for the other variable and then graph ( X, 0) and (0,Y) Draw a line between the two intercepts.

$7 \times 0 + 4 y = 17$ $7 xx 0 + 4y = 17$

$4 y = 17$ $4y = 17$

$\frac{4 y}{4} = \frac{17}{4}$ $(4y)/4 = 17/4$

$y = \frac{17}{4} or 4 \frac{1}{4}$ $y = 17/4 or 4 1/4$

$7 x + 4 \times 0 = 17$ $7x + 4 xx 0 = 17$

$7 x = 17$ $7x = 17$

$\frac{7 x}{7} = \frac{17}{7}$ $(7x) /7 = 17/7$

$x = \frac{17}{7}$ $x = 17/7$

Plot $(0, \frac{17}{4})$ $( 0, 17/4)$ and $(\frac{17}{7}, 0)$ $( 17/7 ,0)$

Connect the two points.

graph{7x+4y=17 [-9.92, 10.08, -2.88, 7.12]}

How do you graph using the intercepts for 7x+4y=177x + 4y = 17?