How do you graph using the intercepts for $x-y=11$ ?

Question

3916 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-01T07:22:12

First, you would find the $x$ and $y$ intercepts for the line. Then, you would connect a line through them.

The $y$ -intercept is $(0,-11)$
The $x$ -intercept is $(11,0)$
graph{x-11 [-10, 10, -5, 5]}

To find the $y$ -intercept: make $x=0$ and solve for $y$ . Your intercept is a point of the form $(0,y)$ .

To find the $x$ -intercept: make $y=0$ and solve for $x$ . Your intercept is a point of the form $(x,0)$ .

We have the equation $x-y=11$

For the $y$ -intercept, let's set $x=0$ and solve for $y$ :
$0-y=11$
$-y=11$
$y=-11$
So the $y$ -intercept is $(0,-11)$

For the $x$ -intercept, let's set $y=0$ and solve for $x$ :
$x-0=11$
$x=11$
So the $x$ -intercept is $(11,0)$

Now, you just plot these two on an $x-y$ plane and connect a straight line through them:

graph{x-11 [-10, 10, -5, 5]}

How do you graph using the intercepts for x-y=11 x-y=11?