How do you graph $x^2/14^2 - y^2/11^2 =1$ ?

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Answer 1 · 2015-11-05T20:00:43

See explanation
The final plot instruction and calculation method given.

I will not bother to square the 14 and 11 for simplicity on my side!

$y^2/11^2 = x^2/14^2 -1$

$y^2 = (11^2x)/14^2 - 11^2$

so
$y= sqrt((11^2x)/14^2 -11^2)$

~~~~~~~~~~~~ Side Note ~~~~~~~~~~~~~~~~~~~~

Suppose $sqrt((11^2x)/14^2 -11^2)= b$

then $(-b) times (-b) =(+b) times (+b) = y$
So the square root can be both positive or negative.

~~~~~~~~~~~ Back to the problem ~~~~~~~~~~~~~~~~~~~~~~~~~

To obtain the plotting values of y

$y = +- sqrt((11^2x)/14^2 -11^2)$

Just insert your values for x and plot both the positive and negative values of $y$ against that value of $x$

How do you graph x^2/14^2 - y^2/11^2 =1x^2/14^2 - y^2/11^2 =1?