How do you graph $(x + 2)^2 + (y + 1)^2 = 32$ ?

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Answer 1 · 2015-10-18T18:47:48

A circle centred at the point $(a,b)$ and having radius $r$ , has equation
$(x-a)^2+(y-b)^2=r^2$

So in this case, $(x+2)^2+(y+1)^2=(sqrt32)^2$ is a circle centred at the point $(-2,-1)$ and having radius $sqrt32$ .

How do you graph (x + 2)^2 + (y + 1)^2 = 32(x + 2)^2 + (y + 1)^2 = 32?