How do you graph $x + 2 y = 8$ $x+2y=8$ using intercepts?

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Answer 1 · 2017-07-06T18:09:06

The x-intercept is $(8, 0)$ $(8,0)$ .

The y-intercept is $(0, 4)$ $(0,4)$ .

Graph:

$x + 2 y = 8$ $x+2y=8$

The x-intercept is the value of $x$ $x$ when $y = 0$ $y=0$ . The y-intercept is the value of $y$ $y$ when $x = 0$ $x=0$ .

To get the x-intercept, substitute $0$ $0$ for $y$ $y$ .

$x + (2 \cdot 0) = 8$ $x+(2*0)=8$

$x = 8$ $x=8$

The x-intercept is $(8, 0)$ $(8,0)$ .

To get the y-intercept, substitute $0$ $0$ for $x$ $x$ .

$0 + 2 y = 8$ $0+2y=8$

$2 y = 8$ $2y=8$

Divide by $2$ $2$ .

$y = 4$ $y=4$

The y-intercept is $(0, 4)$ $(0,4)$ .

You now have two points on the line. You can plot them and then draw a straight line through the points.

graph{x+2y=8 [-12.55, 12.76, -5.42, 7.24]}

How do you graph x+2y=8x+2y=8x+2y=8 using intercepts?