How do you graph $x + 4 y = 12$ $x+4y=12$ by plotting points?

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Answer 1 · 2017-05-01T01:12:21

One way is to find $x$ $x$ and $y$ $y$ -intercepts. Then connect the two points to form your graph.

I noticed that the equation is linear (a degree of $1$ $1$ on variable), therefore, graphing would be easy.

What we can do is to sub each variable as $0$ $0$ and solve for the other.

This will give us the $x$ $x$ and $y$ $y$ -intercepts.

First, the $x$ $x$ -intercept:

$x + 4 y = 12$ $x+4y=12$

$x + 4 (0) = 12$ $x+4(0)=12$

$x = 12$ $x=12$

Therefore, the $x$ $x$ -intercept is $(12, 0)$ $(12, 0)$ .

Now the $y$ $y$ -intercept -

$x + 4 y = 12$ $x+4y=12$

$(0) + 4 y = 12$ $(0)+4y=12$

$4 y = 12$ $4y=12$

Now we can isolate $y$ $y$ .

$\frac{4 y}{4} = \frac{12}{4}$ $(4y)/4=12/4$

$y = 3$ $y=3$

Therefore, the $y$ $y$ -intercept is $(0, 3)$ $(0, 3)$ .

Now that we have two points, we can just connect the two with a straight line and we have our graph.

graph{x+4y=12 [-10, 10, -5, 5]}

Hope this helps :)

How do you graph x+4y=12x+4y=12 by plotting points?