Question

How do you graph `x-4y=12` using intercepts?

Answer 1

Given straight line: `x-4y=12` can be re-written in intercept form as follows

`x/12-{4y}/12=1`

`x/12+y/{-3}=1`

The above straight line has x-intercept `12` & y-intercept `-3`

Take the x-intercept `12` units on x-axis & y-intercept `3` units on -ve y-axis & join both the end-points by a straight line to get the graph/plot

Answer 2

`"see explanation"`

Explanation:

`"to find the intercepts, that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`"let y = 0, in the equation for x-intercept"`

`x=0rArr-4y=12rArry=-3larrcolor(red)"y-intercept"`

`y=0rArrx=12larrcolor(red)"x-intercept"`

`"plot the points "(0,-3)" and "(12,0)`

`"Draw a straight line through them for graph"`
graph{(y-1/4x+3)((x-0)^2+(y+3)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}