How do you graph #x-y=2#?

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Answer 1 · 2018-04-07T18:42:53

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#0 - y = 2#

#-y = 2#

#color(red)(-1) xx -y = color(red)(-1) xx 2#

#y = -2# or #(0, -2)#

Second Point: For #y = 0#

#x - 0 = 2#

#x = 2# or #(2, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.035)((x-2)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x-y-2)(x^2+(y+2)^2-0.035)((x-2)^2+y^2-0.035)=0 [-10, 10, -5, 5]}