How do you graph $x - y = 3$ $x-y=3$ using the x and y intercepts?

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How do you graph $x - y = 3$ $x-y=3$ using the x and y intercepts?

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Answer 1 · 2017-05-27T05:45:24

graph{x-3 [-0.392, 4.62, -3.096, -0.59]}

Explanation:

We can express any linear equation in $t w o$ $two$ variables
in the form
$\frac{x}{a}$ $x/a$ + $\frac{y}{b}$ $y/b$ = $1$ $1$
(here the $e q$ $eq$ will be ( $\frac{x}{a}$ $x/a$ $- \frac{y}{b}$ $-y/b$ = $3$ $3$ )
1.we want to find where the line intersects the y axis

automatically the $v a l u e$ $value$ of $x$ $x$ will become $0$ $0$
we are left with $-$ $-$ $\frac{y}{b}$ $y/b$ = $3$ $3$
by putting $b = 1$ $b=1$ we get $y = - 3$ $y=-3$
the line intersects the y axis at $(0, - 3)$ $(0,-3)$
in the same way we can also find out here the line intersects the axis
it will be $(3, 0)$ $(3,0)$

in terms of plotting the $e q u a t i o n$ $equation$ we will $m a r k$ $mark$ $t h e$ $the$ $t w o$ $two$
points on the $x & y$ $x&y$ and draw a st line $t h r o u g h$ $through$ $t h e m$ $them$

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How do you graph $x - y = 3$ $x-y=3$ using the x and y intercepts?

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How do you graph x−y=3x-y=3 using the x and y intercepts?

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How do you graph $x - y = 3$ $x-y=3$ using the x and y intercepts?