How do you graph $x + y = 5$ $x+y=5$ using intercepts?

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Answer 1 · 2017-06-06T11:11:11

Plot points and connect the dots.

First, plot the $x$ $x$ intercept. You get this by setting $y = 0$ $y=0$ .

$x + 0 = 5$ $x+0=5$

$x = 5$ $x=5$

This gives the point $(5, 0)$ $(5,0)$ , plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.21]}

Next, plot the $y$ $y$ intercept. You get this by setting $x = 0$ $x=0$ .

$0 + y = 5$ $0+y=5$

$y = 5$ $y=5$

This gives the point $(0, 5)$ $(0,5)$ , plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.51]}

Finally, draw a line connecting the two points on the graph. The solution looks like this:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)(x+y-5)=0 [-1.904, 15.874, -3.68, 5.51]}

How do you graph x+y=5x+y=5 using intercepts?