Question

How do you graph `x+y=5` using intercepts?

Answer 1

Plot points and connect the dots.

Explanation:

First, plot the `x` intercept. You get this by setting `y=0`.

`x+0=5`

`x=5`

This gives the point `(5,0)`, plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.21]}

Next, plot the `y` intercept. You get this by setting `x=0`.

`0+y=5`

`y=5`

This gives the point `(0,5)`, plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.51]}

Finally, draw a line connecting the two points on the graph. The solution looks like this:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)(x+y-5)=0 [-1.904, 15.874, -3.68, 5.51]}