How do you graph #y=1/2 sin x#?

1 Answer
Sep 12, 2016

Graph a sine curve with an amplitude of #1/2#.

Explanation:

graph{y=1/2sinx [-10, 10, -5, 5]}

To graph a sine function use
#y=Asin(Bx-C)+D#, where
#A# is amplitude

#(2pi)/B# is period

#C/B# is phase shift

#D# is vertical shift

For #y=1/2sinx#
amplitude=#1/2#
period= #(2pi)/1 = 2pi#
phase shift = 0
vertical shift = 0

In other words, just graph y=sinx, but reduce the amplitude to 1/2. Amplitude is the distance from the "middle" or mean of the curve to the maximum or minimum. Note that it is NOT the distance from max to min.