How do you graph $y = \frac{1}{2} tan (\frac{π}{4} x + \frac{π}{4})$ $y=1/2 tan(pi/4 x + pi/4)$ ?

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How do you graph $y = \frac{1}{2} tan (\frac{π}{4} x + \frac{π}{4})$ $y=1/2 tan(pi/4 x + pi/4)$ ?

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Answer 1 · 2018-06-26T01:40:32

As below.

Explanation:

Standard form of tangent function is $y = A tan (B x - C) + D$ $y = A tan (Bx - C) + D$

$Given : y = (\frac{1}{2}) tan ((\frac{π}{4}) x + \frac{π}{4})$ $"Given : " y = (1/2) tan ((pi/4)x + pi/4)$

$A = \frac{1}{2}, b = \frac{π}{4}, c = - \frac{π}{4}, D = 0$ $A = 1/2, b = pi/4, c = -pi/4, D = 0$

$Amplitude = | A | = NONE for tangent function$ $"Amplitude " = |A| = "NONE for tangent function"$

$Period = \frac{π}{| B |} = \frac{π}{\frac{π}{4}} = 4$ $"Period " = pi/|B| = pi/ (pi/4) = 4$

$Phase Shift = - \frac{C}{B} = - \frac{\frac{π}{4}}{\frac{π}{4}} = - 1, 1 to the LEFT$ $"Phase Shift" = -C / B = -(pi/4) / (pi/4) = -1, " 1 to the LEFT"$

$Vertical Shift = D = 0$ $"Vertical Shift " = D = 0$

graph{(1/2) tan((pi/4)x + pi/4) [-10, 10, -5, 5]}

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How do you graph $y = \frac{1}{2} tan (\frac{π}{4} x + \frac{π}{4})$ $y=1/2 tan(pi/4 x + pi/4)$ ?

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Explanation:

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