How do you graph #y = 1/2x + 2# by plotting points?
1 Answer
The graph would look like this:
graph{1/2x+2 [-10, 10, -5, 5]}
Explanation:
Since the equation is already in the form of
Therefore, first, you would plot a point on the y-axis. Since the y-intercept is 2, you would plot it on (0,2).
Then, you would graph another point in a spot by moving two spaces to the right and one space up from your y-intercept. You can repeat the process if you want to.
If you want to plot a point that is located to the left side of the y-intercept, simply graph a point on the spot by moving one space down and two spaces to the left.
Lastly, you could connect the points and extend them.